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JEE Main 2019 · 12 Apr · Shift II

JEE Main 2019 Mathematics question on Conic Sections

If the normal to the ellipse 3x2+4y2=123x^2 + 4y^2 = 12 at a point PP on it is parallel to the line, 2x+y=42x + y = 4 and the tangent to the ellipse at PP passes through Q(4,1)Q(4, 1) then PQPQ is equal to
  1. A.
    552\dfrac{5\sqrt{5}}{2}
  2. B.
    612\dfrac{\sqrt{61}}{2}
  3. C.
    2212\dfrac{\sqrt{221}}{2}
  4. D.
    1572\dfrac{\sqrt{157}}{2}
Show answer

Correct option: A

[JEE Main 2019 · 12 Apr · Shift II]

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