JEE Main 2019 · 11 Jan · Shift II

JEE Main 2019 Mathematics question on Conic Sections

If the area of the triangle whose one vertex is at the vertex of the parabola, y2+4(x−a2)=0y^2 + 4(x - a^2) = 0 and the other two vertices are the points of intersection of the parabola and Y-axis, is 250 sq units, then a value of 'aa' is
  1. A.
    555\sqrt{5}
  2. B.
    55
  3. C.
    5(21/3)5(2^{1/3})
  4. D.
    (10)2/3(10)^{2/3}
Show answer

Correct option: B

[JEE Main 2019 · 11 Jan · Shift II]

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