JEE Main 2019 · 12 Apr · Shift II

JEE Main 2019 Mathematics question on Definite Integrals and Areas

If the area (in sq units) of the region {(x,y):y2≤4x,x+y≤1,x≥0,y≥0}\{(x, y): y^2 \leq 4x, x + y \leq 1, x \geq 0, y \geq 0\} is a2+ba\sqrt{2} + b, then a−ba - b is equal to
  1. A.
    103\dfrac{10}{3}
  2. B.
    66
  3. C.
    83\dfrac{8}{3}
  4. D.
    −23-\dfrac{2}{3}
Show answer

Correct option: B

[JEE Main 2019 · 12 Apr · Shift II]

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