JEE Main 2019 · 10 Jan · Shift II

JEE Main 2019 Mathematics question on Permutations and Combinations

If ∑r=125{50Cr⋅50−rC25−r}=K(50C25)\sum_{r=1}^{25} \{{}^{50}C_r \cdot {}^{50-r}C_{25-r}\} = K({}^{50}C_{25}),

then, KK is equal to
  1. A.
    2242^{24}
  2. B.
    225−12^{25} - 1
  3. C.
    2252^{25}
  4. D.
    (25)2(25)^2
Show answer

Correct option: C

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