JEE Main 2019 · 12 Jan · Shift II

JEE Main 2019 Mathematics question on Trigonometry

If sin⁡4α+4cos⁡4β+2=42sin⁡αcos⁡β\sin^4 \alpha + 4\cos^4 \beta + 2 = 4\sqrt{2}\sin\alpha\cos\beta; α,β∈[0,π]\alpha, \beta \in [0, \pi], then cos⁡(α+β)−cos⁡(α−β)\cos(\alpha + \beta) - \cos(\alpha - \beta) is equal to
  1. A.
    −1-1
  2. B.
    2\sqrt{2}
  3. C.
    −2-\sqrt{2}
  4. D.
    00
Show answer

Correct option: C

[JEE Main 2019 · 12 Jan · Shift II]

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