AIEEE 2012

JEE Main 2012 Mathematics question on Matrices and Determinants

If PP is a 3×33 \times 3 matrix such that PT=2P+IP^T = 2P + I, where PTP^T is the transpose of PP and II is the 3×33 \times 3 identity matrix, then there exists a column matrix, X=[xyz]≠[000]X = \begin{bmatrix} x \\ y \\ z \end{bmatrix} \neq \begin{bmatrix} 0 \\ 0 \\ 0 \end{bmatrix} such that
  1. A.
    PX=[000]PX = \begin{bmatrix} 0 \\ 0 \\ 0 \end{bmatrix}
  2. B.
    PX=XPX = X
  3. C.
    PX=2XPX = 2X
  4. D.
    PX=−XPX = -X
Show answer and solution

Correct option: D

Solution

From PT = 2P + I, take the transpose of both sides:

P = 2PT + I

Substitute PT = 2P + I into this:

P = 2(2P + I) + I = 4P + 3I

So -3P = 3I, giving P = -I.

Then PX = -IX = -X for any nonzero column vector X.

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