JEE Main 2019 · 9 Jan · Shift II
JEE Main 2019 Mathematics question on Straight Lines and Pair of Lines
If lines
x=ay+b,
z=cy+d and
x=a′z+b′,
y=c′z+d′ are perpendicular, then
- A.
ab′+bc′+1=0 - B.
bb′+cc′+1=0 - C.
aa′+c+c′=0 - D.
cc′+a+a′=0
Show answer and solution
Correct option: C
Solution
The first line can be written with y as parameter: direction ratios are (a, 1, c).
The second line with z as parameter: x = a'z + b', y = c'z + d', so direction ratios are (a', c', 1).
For perpendicularity, the dot product of direction vectors = 0:
a·a' + 1·c' + c·1 = 0
→ aa' + c' + c = 0, i.e., aa' + c + c' = 0.
[JEE Main 2019 · 9 Jan · Shift II]
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