JEE Main 2018

JEE Main 2018 Mathematics question on Three Dimensional Geometry

If L1L_1 is the line of intersection of the planes 2x−2y+3z−2=02x - 2y + 3z - 2 = 0, x−y+z+1=0x - y + z + 1 = 0 and L2L_2 is the line of intersection of the planes x+2y−z−3=0x + 2y - z - 3 = 0, 3x−y+2z−1=03x - y + 2z - 1 = 0, then the distance of the origin from the plane, containing the lines L1L_1 and L2L_2 is
  1. A.
    142\dfrac{1}{4\sqrt{2}}
  2. B.
    132\dfrac{1}{3\sqrt{2}}
  3. C.
    122\dfrac{1}{2\sqrt{2}}
  4. D.
    12\dfrac{1}{\sqrt{2}}
Show answer

Correct option: B

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