AIEEE 2003

JEE Main 2003 Mathematics question on Sets Relations and Functions

If f:[0,∞)→[0,∞)f:[0,\infty) \to [0,\infty) and f(x)=x1+xf(x) = \dfrac{x}{1+x}, then ff is \hfill
  1. A.
    one-one and onto
  2. B.
    one-one but not onto
  3. C.
    onto but not one-one
  4. D.
    neither one-one nor onto
Show answer and solution

Correct option: B

Solution

f'(x) = 1/(1+x)² > 0 for all x ≥ 0, so f is strictly increasing, hence one-one. The range of f is [0, 1) since x/(1+x) → 1 as x → ∞ but never reaches 1, while the codomain is [0, ∞). Since 1 ∈ [0, ∞) has no preimage, f is not onto.

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