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JEE Main 2019 · 11 Jan · Shift I

JEE Main 2019 Mathematics question on Indefinite Integration

If ∫1−x2x4dx=A(x)(1−x2)m+C\int \dfrac{\sqrt{1-x^2}}{x^4} dx = A(x)(\sqrt{1-x^2})^m + C, for a suitable chosen integer mm and a function A(x)A(x), where CC is a constant of integration, then (A(x))m(A(x))^m equals
  1. A.
    −19x4\dfrac{-1}{9x^4}
  2. B.
    13x3\dfrac{1}{3x^3}
  3. C.
    −127x3\dfrac{-1}{27x^3}
  4. D.
    127x6\dfrac{1}{27x^6}
Show answer

Correct option: C

[JEE Main 2019 · 11 Jan · Shift I]

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