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JEE Main 2019 · 11 Jan · Shift II

JEE Main 2019 Mathematics question on Matrices and Determinants

If ∣a−b−c2a2a2bb−c−a2b2c2cc−a−b∣\begin{vmatrix} a-b-c & 2a & 2a \\ 2b & b-c-a & 2b \\ 2c & 2c & c-a-b \end{vmatrix}
=(a+b+c)(x+a+b+c)2, x≠0= (a+b+c)(x+a+b+c)^2,\, x \neq 0 and a+b+c≠0a+b+c \neq 0, then xx is equal to
  1. A.
    −(a+b+c)-(a+b+c)
  2. B.
    −2(a+b+c)-2(a+b+c)
  3. C.
    2(a+b+c)2(a+b+c)
  4. D.
    abcabc
Show answer

Correct option: B

[JEE Main 2019 · 11 Jan · Shift II]

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