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JEE Main 2019 · 12 Jan · Shift I

JEE Main 2019 Mathematics question on Complex Numbers and Quadratic Equations

If λ\lambda be the ratio of the roots of the quadratic equation in xx, 3m2x2+m(m−4)x+2=03m^2x^2 + m(m-4)x + 2 = 0, then the least value of mm for which λ+1λ=1\lambda + \frac{1}{\lambda} = 1, is
  1. A.
    −2+2-2 + \sqrt{2}
  2. B.
    4−324 - 3\sqrt{2}
  3. C.
    −2+43-2 + 4\sqrt{3}
  4. D.
    2−32 - \sqrt{3}
Show answer

Correct option: C

[JEE Main 2019 · 12 Jan · Shift I]

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