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1988

JEE Main 1988 Mathematics question on Circles

If a circle passes through the point (a,b)(a, b) and cuts the circle x2+y2=k2x^2 + y^2 = k^2 orthogonally, then the equation of the locus of its centre is
  1. A.
    2ax+2by−(a2+b2+k2)=02ax + 2by - (a^2 + b^2 + k^2) = 0
  2. B.
    2ax+2by−(a2−b2+k2)=02ax + 2by - (a^2 - b^2 + k^2) = 0
  3. C.
    x2+y2−3ax−4by+(a2+b2−k2)=0x^2 + y^2 - 3ax - 4by + (a^2 + b^2 - k^2) = 0
  4. D.
    x2+y2−2ax−3by+(a2−b2−k2)=0x^2 + y^2 - 2ax - 3by + (a^2 - b^2 - k^2) = 0
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Correct option: A

[1988]

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