If are non-coplanar unit vectors such that , then the angle between and is
- A.
- B.
- C.
- D.
Show answer and solution
Correct option: A
Solution
Using the BAC-CAB rule: a×(b×c) = (a·c)b - (a·b)c = (b+c)/√2.
So (a·c) = 1/√2 and -(a·b) = 1/√2, giving a·b = -1/√2.
Since all are unit vectors, a·b = |a||b|cosθ = cosθ = -1/√2, so θ = 3π/4.
So (a·c) = 1/√2 and -(a·b) = 1/√2, giving a·b = -1/√2.
Since all are unit vectors, a·b = |a||b|cosθ = cosθ = -1/√2, so θ = 3π/4.
[1995]