1998

JEE Main 1998 Mathematics question on Complex Numbers and Quadratic Equations

If A0,A1,A2,A3,A4A_0, A_1, A_2, A_3, A_4 and A5A_5 be a regular hexagon inscribed in a circle of unit radius. Then, the product of the lengths of the line segments A0A1A_0A_1, A0A2A_0A_2 and A0A4A_0A_4 is
  1. A.
    3/43/4
  2. B.
    333\sqrt{3}
  3. C.
    33
  4. D.
    332\dfrac{3\sqrt{3}}{2}
Show answer and solution

Correct option: C

Solution

The vertices of a regular hexagon inscribed in a unit circle are separated by 60° each. The chord length between vertices k steps apart is 2sin(kπ/6).

- A₀A₁: 1 step apart → 2sin(π/6) = 2·(1/2) = 1
- A₀A₂: 2 steps apart → 2sin(2π/6) = 2sin(π/3) = √3
- A₀A₄: 4 steps apart (equivalently 2 steps the other way) → 2sin(4π/6) = 2sin(2π/3) = √3

Product = 1 · √3 · √3 = 3.

[1998]

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