JEE Main 2019 · 12 Apr · Shift II

JEE Main 2019 Mathematics question on Binomial Theorem

If 20C1+(22) 20C2+(32) 20C3+…+(202) 20C20=A(2β)^{20}C_1 + (2^2)\,^{20}C_2 + (3^2)\,^{20}C_3 + \ldots + (20^2)\,^{20}C_{20} = A(2^\beta), then the ordered pair (A,β)(A, \beta) is equal to
  1. A.
    (420, 19)
  2. B.
    (420, 18)
  3. C.
    (380, 18)
  4. D.
    (380, 19)
Show answer

Correct option: B

[JEE Main 2019 · 12 Apr · Shift II]

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