JEE Main 2017
JEE Main 2017 Mathematics question on Differential Equations
If
(2+sinx)dxdy+(y+1)cosx=0 and
y(0)=1, then
y(2π) is equal to
- A.
- B.
- C.
- D.
Show answer and solution
Correct option: A
Solution
Separate variables: dy/(y+1) = -cos x dx/(2+sin x).
Integrate both sides: ln|y+1| = -ln|2+sin x| + C, so (y+1)(2+sin x) = K.
Apply y(0)=1: (1+1)(2+0) = K → K = 4.
At x = π/2: (y+1)(2+1) = 4 → y+1 = 4/3 → y = 1/3.
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