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JEE Main 2023 · 24 Jan · Shift 1 · Paper-1(B.E./B. Tech.)

JEE Main 2023 Mathematics question on Sequences and Series

For three positive integers p, q, r, xpq2=yqr=zp2rx^{pq^2} = y^{qr} = z^{p^2r} and r=pq+1r = pq + 1 such that 3,3log⁡yx,3log⁡zy,7log⁡xz3, 3\log_y x, 3\log_z y, 7\log_x z are in A.P. with common difference 12\frac{1}{2}. Then r−p−qr - p - q is equal to
  1. A.
    2
  2. B.
    −6-6
  3. C.
    6
  4. D.
    12
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Correct option: A

[JEE Main 2023 · 24 Jan · Shift 1 · Paper-1(B.E./B. Tech.)]

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