1996

JEE Main 1996 Mathematics question on Probability

For the three events AA, BB and CC, PP(exactly one of the events AA or BB occurs) =P= P(exactly one of the events BB or CC occurs) =P= P(exactly one of the events CC or AA occurs) =p= p and PP(all the three events occurs simultaneously) =p2= p^2, where 0<p<120 < p < \frac{1}{2}. Then, the probability of atleast one of the three events AA, BB and CC occurring is
  1. A.
    3p+2p22\dfrac{3p + 2p^2}{2}
  2. B.
    p+3p24\dfrac{p + 3p^2}{4}
  3. C.
    p+3p22\dfrac{p + 3p^2}{2}
  4. D.
    3p+2p24\dfrac{3p + 2p^2}{4}
Show answer

Correct option: A

[1996]

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