For independent processes at 300 K
The number of non-spontaneous processes from the following is ______
| Process | /kJ mol | /J K |
|---|---|---|
| A | ||
| B | ||
| C | ||
| D |
The number of non-spontaneous processes from the following is ______
Show answer and solution
Answer: 2
Solution
Calculate ΔG = ΔH - TΔS at T = 300 K for each process (spontaneous if ΔG < 0):
A: ΔG = -25000 - 300(-80) = -25000 + 24000 = -1000 J/mol < 0 → Spontaneous
B: ΔG = -22000 - 300(40) = -22000 - 12000 = -34000 J/mol < 0 → Spontaneous
C: ΔG = 25000 - 300(-50) = 25000 + 15000 = 40000 J/mol > 0 → Non-spontaneous
D: ΔG = 22000 - 300(20) = 22000 - 6000 = 16000 J/mol > 0 → Non-spontaneous
Processes C and D are non-spontaneous, giving the answer 2.
A: ΔG = -25000 - 300(-80) = -25000 + 24000 = -1000 J/mol < 0 → Spontaneous
B: ΔG = -22000 - 300(40) = -22000 - 12000 = -34000 J/mol < 0 → Spontaneous
C: ΔG = 25000 - 300(-50) = 25000 + 15000 = 40000 J/mol > 0 → Non-spontaneous
D: ΔG = 22000 - 300(20) = 22000 - 6000 = 16000 J/mol > 0 → Non-spontaneous
Processes C and D are non-spontaneous, giving the answer 2.
[JEE Main 2023 · 24 Jan · Shift 1 · Paper-1(B.E./B. Tech.)]