AIEEE 2005

JEE Main 2005 Mathematics question on Sets Relations and Functions

f(x)={x,if x is rational0,if x is irrationalf(x) = \begin{cases} x, & \text{if } x \text{ is rational} \\ 0, & \text{if } x \text{ is irrational} \end{cases}, g(x)={0,if x is rationalx,if x is irrationalg(x) = \begin{cases} 0, & \text{if } x \text{ is rational} \\ x, & \text{if } x \text{ is irrational} \end{cases}

Then, f−gf - g is
  1. A.
    one-one and into
  2. B.
    neither one-one nor onto
  3. C.
    many-one and onto
  4. D.
    one-one and onto
Show answer

Correct option: D

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