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JEE Main 2019 · 11 Jan · Shift I

JEE Main 2019 Mathematics question on Conic Sections

Equation of a common tangent to the parabola y2=4xy^2 = 4x and the hyperbola xy=2xy = 2 is
  1. A.
    x+2y+4=0x + 2y + 4 = 0
  2. B.
    x−2y+4=0x - 2y + 4 = 0
  3. C.
    4x+2y+1=04x + 2y + 1 = 0
  4. D.
    x+y+1=0x + y + 1 = 0
Show answer

Correct option: A

[JEE Main 2019 · 11 Jan · Shift I]

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