JEE Main 2019 · 10 Jan · Shift I

JEE Main 2019 Mathematics question on Trigonometry

Consider a triangular plot ABCABC with sides AB=7AB = 7 m, BC=5BC = 5 m and CA=6CA = 6 m. A vertical lamp-post at the mid-point DD of ACAC subtends an angle 30°30° at BB. The height (in m) of the lamp-post is
  1. A.
    2321\dfrac{2}{3}\sqrt{21}
  2. B.
    2212\sqrt{21}
  3. C.
    737\sqrt{3}
  4. D.
    3221\dfrac{3}{2}\sqrt{21}
Show answer and solution

Correct option: A

Solution

Find BD first using the median formula. D is the midpoint of AC, so BD is a median from B with AB=7, BC=5, AC=6.

BD² = (2·AB² + 2·BC² - AC²)/4 = (2·49 + 2·25 - 36)/4 = (98 + 50 - 36)/4 = 112/4 = 28, so BD = 2√7.

The lamp-post of height h at D subtends 30° at B, meaning tan(30°) = h/BD.

h = BD · tan(30°) = 2√7 · (1/√3) = 2√7/√3 = 2√(7/3) = (2/3)√21.

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