JEE Main 2019 · 10 Apr · Shift I

JEE Main 2019 Mathematics question on Trigonometry

All the pairs (x,y)(x, y) that satisfy the inequality 2sin⁡2x−2sin⁡x+5⋅14sin⁡2y≤12^{\sqrt{\sin^2 x - 2\sin x + 5}} \cdot \dfrac{1}{4^{\sin^2 y}} \leq 1 also satisfy the equation
  1. A.
    sin⁡x=∣sin⁡y∣\sin x = |\sin y|
  2. B.
    sin⁡x=2sin⁡y\sin x = 2\sin y
  3. C.
    2∣sin⁡x∣=sin⁡y2|\sin x| = \sin y
  4. D.
    2sin⁡x=sin⁡y2\sin x = \sin y
Show answer

Correct option: B

[JEE Main 2019 · 10 Apr · Shift I]

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