JEE Main 2019 · 12 Apr · Shift II

JEE Main 2019 Mathematics question on Straight Lines and Pair of Lines

A triangle has a vertex at (1, 2) and the mid-points of the two sides through it are (−1,1)(-1, 1) and (2,3)(2, 3). Then, the centroid of this triangle is
  1. A.
    (1,73)\left(1, \dfrac{7}{3}\right)
  2. B.
    (13,2)\left(\dfrac{1}{3}, 2\right)
  3. C.
    (13,1)\left(\dfrac{1}{3}, 1\right)
  4. D.
    (13,53)\left(\dfrac{1}{3}, \dfrac{5}{3}\right)
Show answer and solution

Correct option: B

Solution

Let vertex A = (1,2). The midpoints of the two sides through A are M₁ = (-1,1) and M₂ = (2,3).

Since M₁ is the midpoint of AB: B = (2(-1)-1, 2(1)-2) = (-3, 0).
Since M₂ is the midpoint of AC: C = (2(2)-1, 2(3)-2) = (3, 4).

Centroid = ((1+(-3)+3)/3, (2+0+4)/3) = (1/3, 6/3) = (1/3, 2).

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