A student has studied the decomposition of a gas at 25°C. He obtained the following data.
The order of the reaction is
| p (mm Hg) | 50 | 100 | 200 | 400 |
|---|---|---|---|---|
| relative (s) | 4 | 2 | 1 | 0.5 |
The order of the reaction is
- A.
- B.
- C.(zero)
- D.
Show answer and solution
Correct option: A
Solution
For an nth order reaction, t₁/₂ ∝ 1/p^(n-1).
From the data, when pressure doubles (50→100), t₁/₂ halves (4→2). So t₁/₂ ∝ 1/p, meaning 1/p^(n-1) ∝ 1/p, which gives n-1 = 1, so n = 2.
The order of the reaction is 2.
From the data, when pressure doubles (50→100), t₁/₂ halves (4→2). So t₁/₂ ∝ 1/p, meaning 1/p^(n-1) ∝ 1/p, which gives n-1 = 1, so n = 2.
The order of the reaction is 2.
[JEE Main 2023 · 24 Jan · Shift 2]