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JEE Main 2019 · 11 Jan · Shift II

JEE Main 2019 Mathematics question on Circles

A square is inscribed in the circle x2+y2−6x+8y−103=0x^2 + y^2 - 6x + 8y - 103 = 0 with its sides parallel to the coordinate axes. Then, the distance of the vertex of this square which is nearest to the origin is
  1. A.
    6
  2. B.
    13
  3. C.
    41\sqrt{41}
  4. D.
    137\sqrt{137}
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Correct option: C

[JEE Main 2019 · 11 Jan · Shift II]

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