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JEE Main 2023 · 25 Jan · Shift 1

JEE Main 2023 Physics question on Magnetism and Moving Charges

A solenoid of 1200 turns is wound uniformly in a single layer on a glass tube 2 m long and 0.2 m in diameter. The magnetic intensity at the center of the solenoid when a current of 2 A flows through it is:
  1. A.
    1.2×103 A m−11.2 \times 10^3 \text{ A m}^{-1}
  2. B.
    1 A m−11 \text{ A m}^{-1}
  3. C.
    2.4×103 A m−12.4 \times 10^3 \text{ A m}^{-1}
  4. D.
    2.4×10−3 A m−12.4 \times 10^{-3} \text{ A m}^{-1}
Show answer and solution

Correct option: A

Solution

H = nI, where n = N/L = 1200/2 = 600 turns/m. So H = 600 × 2 = 1200 = 1.2 × 10³ A m⁻¹. Note that H inside a solenoid depends only on turn density and current, not on the diameter or core material (glass).

[JEE Main 2023 · 25 Jan · Shift 1]

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