AIEEE 2004

JEE Main 2004 Physics question on Kinematics

A particle starts from rest. Its acceleration (a) versus time (t) is as shown in the figure. The maximum speed of the particle will be (2004, 2M)

  1. A.
    (a) 110 m/s
  2. B.
    (b) 55 m/s
  3. C.
    (c) 550 m/s
  4. D.
    (d) 660 m/s
Show answer and solution

Correct option: B

Solution

The maximum speed is the area under the a-t graph. From the standard version of this problem, the graph shows acceleration decreasing linearly from 10 m/s² at t = 0 to 0 at t = 11 s. The area under this triangle is (1/2) × base × height = (1/2) × 11 × 10 = 55 m/s.

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