A particle executes simple harmonic motion between and . If time taken by particle to go from to is 2 s; then time taken by particle in going from to is
- A.3 s
- B.1.5 s
- C.2 s
- D.4 s
Show answer and solution
Correct option: D
Solution
In SHM, x = A sin(ωt). Time to go from x = 0 to x = A/2: A/2 = A sin(ωt₁), so sin(ωt₁) = 1/2, giving ωt₁ = π/6, so t₁ = 2 s means ω = π/12 rad/s.
Time to go from x = 0 to x = A: ωt₂ = π/2, so t₂ = (π/2)/ω = (π/2)/(π/12) = 6 s.
Time from x = A/2 to x = A = t₂ − t₁ = 6 − 2 = 4 s.
Time to go from x = 0 to x = A: ωt₂ = π/2, so t₂ = (π/2)/ω = (π/2)/(π/12) = 6 s.
Time from x = A/2 to x = A = t₂ − t₁ = 6 − 2 = 4 s.
[JEE Main 2023 · 25 Jan · Shift 2]