JEE Main 2023 · 25 Jan · Shift 2 · numerical answer

JEE Main 2023 Physics question on Atoms and Nuclei

A nucleus disintegrates into two smaller parts, which have their velocities in the ratio 3:2. The ratio of their nuclear sizes will be (x3)13\left(\frac{x}{3}\right)^{\frac{1}{3}}. The value of 'x' is:-
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Answer: 2

Solution

By conservation of momentum, m₁v₁ = m₂v₂, so m₁/m₂ = v₂/v₁ = 2/3.

Since mass number A ∝ R³, we have R₁/R₂ = (A₁/A₂)^(1/3) = (2/3)^(1/3) = (2/3)^(1/3).

This equals (x/3)^(1/3), so x = 2.

[JEE Main 2023 · 25 Jan · Shift 2]

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