JEE Main 2019 · 11 Jan · Shift I

JEE Main 2019 Physics question on Kinematics

A body is projected at t=0t = 0 with a velocity 10 ms−110 \text{ ms}^{-1} at an angle of 60°60° with the horizontal. The radius of curvature of its trajectory at t=1t = 1 s is RR. Neglecting air resistance and taking acceleration due to gravity g=10 ms−2g = 10 \text{ ms}^{-2}, the value of RR is
  1. A.
    10.3 m
  2. B.
    2.8 m
  3. C.
    5.1 m
  4. D.
    2.5 m
Show answer

Correct option: B

[JEE Main 2019 · 11 Jan · Shift I]

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