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JEE Main 2019 · 10 Apr · Shift I

JEE Main 2019 Physics question on Kinematics

A ball is thrown upward with an initial velocity v0v_0 from the surface of the earth. The motion of the ball is affected by a drag force equal to mγv2m\gamma v^2 (where, mm is mass of the ball, vv is its instantaneous velocity and γ\gamma is a constant). Time taken by the ball to rise to its zenith is
  1. A.
    12gtan⁡−1(2γg v0)\dfrac{1}{\sqrt{2g}} \tan^{-1}\left(\sqrt{\dfrac{2\gamma}{g}}\, v_0\right)
  2. B.
    1gtan⁡−1(γg v0)\dfrac{1}{\sqrt{g}} \tan^{-1}\left(\sqrt{\dfrac{\gamma}{g}}\, v_0\right)
  3. C.
    1γgsin⁡−1(γg v0)\dfrac{1}{\sqrt{\gamma g}} \sin^{-1}\left(\sqrt{\dfrac{\gamma}{g}}\, v_0\right)
  4. D.
    1γgln⁡(1+γg v0)\dfrac{1}{\sqrt{\gamma g}} \ln\left(1 + \sqrt{\dfrac{\gamma}{g}}\, v_0\right)
Show answer

Correct option: B

[JEE Main 2019 · 10 Apr · Shift I]

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