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JEE Main 2017

JEE Main 2017 Chemistry question on Some Basic Concepts of Chemistry

1 g of a carbonate (M2CO3)(M_2CO_3) on treatment with excess HCl produces 0.01186 mole of CO2CO_2. The molar mass of M2CO3M_2CO_3 in g mol−1^{-1} is
  1. A.
    1186
  2. B.
    84.3
  3. C.
    118.6
  4. D.
    11.86
Show answer and solution

Correct option: B

Solution

The reaction is M₂CO₃ + 2HCl → 2MCl + H₂O + CO₂, so moles of M₂CO₃ = moles of CO₂ = 0.01186 mol.

Molar mass = mass / moles = 1 g / 0.01186 mol ≈ 84.3 g mol⁻¹.

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