1984

JEE Main 1984 Mathematics question on Trigonometry

(1+cos⁡π8)(1+cos⁡3π8)(1+cos⁡5π8)(1+cos⁡7π8)\left(1 + \cos\dfrac{\pi}{8}\right)\left(1 + \cos\dfrac{3\pi}{8}\right)\left(1 + \cos\dfrac{5\pi}{8}\right)\left(1 + \cos\dfrac{7\pi}{8}\right) is equal to
  1. A.
    12\dfrac{1}{2}
  2. B.
    cos⁡π8\cos\dfrac{\pi}{8}
  3. C.
    18\dfrac{1}{8}
  4. D.
    1+222\dfrac{1+\sqrt{2}}{2\sqrt{2}}
Show answer

Correct option: C

[1984]

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