JEE Advanced 2024 · Paper 1 · one or more correct

JEE Advanced 2024 Physics question on Oscillations and Waves

Two uniform strings of mass per unit length μ\mu and 4μ4\mu, and length LL and 2L2L, respectively, are joined at point O, and tied to two fixed ends P and Q, as shown in the figure. The strings are under a uniform tension TT. If we define the frequency ν0=12LTμ\nu_0 = \dfrac{1}{2L}\sqrt{\dfrac{T}{\mu}}, which of the following statement(s) is(are) correct?
  1. A.
    With a node at O, the minimum frequency of vibration of the composite string is ν0\nu_0.
  2. B.
    With an antinode at O, the minimum frequency of vibration of the composite string is 2ν02\nu_0.
  3. C.
    When the composite string vibrates at the minimum frequency with a node at O, it has 6 nodes, including the end nodes.
  4. D.
    No vibrational mode with an antinode at O is possible for the composite string.
Show answer

Correct options: A, C, D

[JEE Advanced 2024 · Paper 1]

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