JEE Advanced 2024 · Paper 2 · numerical answer

JEE Advanced 2024 Physics question on Ray Optics

Two equilateral-triangular prisms P1P_1 and P2P_2 are kept with their sides parallel to each other, in vacuum, as shown in the figure. A light ray enters prism P1P_1 at an angle of incidence θ\theta such that the outgoing ray undergoes minimum deviation in prism P2P_2. If the respective refractive indices of P1P_1 and P2P_2 are 32\sqrt{\dfrac{3}{2}} and 3\sqrt{3}, then θ=sin⁡−1[32sin⁡(πβ)]\theta = \sin^{-1}\left[\sqrt{\dfrac{3}{2}}\sin\left(\dfrac{\pi}{\beta}\right)\right], where the value of β\beta is ______.
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Answer: 12

[JEE Advanced 2024 · Paper 2]

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