JEE Advanced 2024 · Paper 1

JEE Advanced 2024 Physics question on Electrostatics

Two beads, each with charge qq and mass mm, are on a horizontal, frictionless, non-conducting, circular hoop of radius RR. One of the beads is glued to the hoop at some point, while the other one performs small oscillations about its equilibrium position along the hoop. The square of the angular frequency of oscillation is given by

[ε0\varepsilon_0 is the permittivity of free space.]
  1. A.
    q2/(4πε0R3m)q^2/(4\pi\varepsilon_0 R^3 m)
  2. B.
    q2/(32πε0R3m)q^2/(32\pi\varepsilon_0 R^3 m)
  3. C.
    q2/(8πε0R3m)q^2/(8\pi\varepsilon_0 R^3 m)
  4. D.
    q2/(16πε0R3m)q^2/(16\pi\varepsilon_0 R^3 m)
Show answer

Correct option: B

[JEE Advanced 2024 · Paper 1]

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