To form a complete monolayer of acetic acid on 1g of charcoal, 100 mL of 0.5 M acetic acid was used. Some of the acetic acid remained unadsorbed. To neutralize the unadsorbed acetic acid, 40 mL of 1 M NaOH solution was required. If each molecule of acetic acid occupies P x m surface area on charcoal, the value of P is _____.
[Use given data: Surface area of charcoal = 1.5 x mg; Avogadro's number (N) = 6.0 x mol]
[Use given data: Surface area of charcoal = 1.5 x mg; Avogadro's number (N) = 6.0 x mol]
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Answer: 2500
[JEE Advanced 2024 · Paper 2]