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JEE Advanced 2023 · Paper 1

JEE Advanced 2023 Physics question on Electromagnetic Waves

Match the temperature of a black body given in List-I with an appropriate statement in List-II, and choose the correct option.
[Given: Wien's constant as 2.9×10−32.9 \times 10^{-3} m-K and hce=1.24×10−6\dfrac{hc}{e} = 1.24 \times 10^{-6} V-m]
List-I
(P) 20002000 K
(Q) 30003000 K
(R) 50005000 K
(S) 1000010000 K
List-II
(1) The radiation at peak wavelength can lead to emission of photoelectrons from a metal of work function 4 eV.
(2) The radiation at peak wavelength is visible to human eye.
(3) The radiation at peak emission wavelength will result in the widest central maximum of a single slit diffraction.
(4) The power emitted per unit area is 1/161/16 of that emitted by a blackbody at temperature 6000 K.
(5) The radiation at peak emission wavelength can be used to image human bones.
  1. A.
    P→3,Q→5,R→2,S→3P \rightarrow 3, Q \rightarrow 5, R \rightarrow 2, S \rightarrow 3
  2. B.
    P→3,Q→2,R→4,S→1P \rightarrow 3, Q \rightarrow 2, R \rightarrow 4, S \rightarrow 1
  3. C.
    P→3,Q→4,R→2,S→1P \rightarrow 3, Q \rightarrow 4, R \rightarrow 2, S \rightarrow 1
  4. D.
    P→1,Q→2,R→5,S→3P \rightarrow 1, Q \rightarrow 2, R \rightarrow 5, S \rightarrow 3
Show answer

Correct option: C

[JEE Advanced 2023 · Paper 1]

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