JEE Advanced 2023 · Paper 1 · numerical answer

JEE Advanced 2023 Mathematics question on Trigonometry

Let tan⁡−1(x)∈(−π2,π2)\tan^{-1}(x) \in \left(-\dfrac{\pi}{2}, \dfrac{\pi}{2}\right), for x∈Rx \in \mathbb{R}. Then the number of real solutions of the equation 1+cos⁡(2x)=2 tan⁡−1(tan⁡x)\sqrt{1+\cos(2x)} = \sqrt{2}\, \tan^{-1}(\tan x) in the set (−3π2,−π2)∪(−π2,π2)∪(π2,3π2)\left(-\dfrac{3\pi}{2}, -\dfrac{\pi}{2}\right) \cup \left(-\dfrac{\pi}{2}, \dfrac{\pi}{2}\right) \cup \left(\dfrac{\pi}{2}, \dfrac{3\pi}{2}\right) is equal to
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Answer: 3

[JEE Advanced 2023 · Paper 1]

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