JEE Advanced 2023 · Paper 1 · numerical answer

JEE Advanced 2023 Mathematics question on Vector Algebra

Let PP be the plane 3x+2y+3z=16\sqrt{3}x + 2y + 3z = 16 and let
S={αi^+βj^+γk^:α2+β2+γ2=1 and the distance of (α,β,γ) from the plane P is 72}S = \left\{\alpha\hat{i} + \beta\hat{j} + \gamma\hat{k} : \alpha^2 + \beta^2 + \gamma^2 = 1 \text{ and the distance of } (\alpha, \beta, \gamma) \text{ from the plane } P \text{ is } \dfrac{7}{2}\right\}.
Let u⃗,v⃗\vec{u}, \vec{v} and w⃗\vec{w} be three distinct vectors in SS such that ∣u⃗−v⃗∣=∣v⃗−w⃗∣=∣w⃗−u⃗∣|\vec{u} - \vec{v}| = |\vec{v} - \vec{w}| = |\vec{w} - \vec{u}|. Let VV be the volume of the parallelepiped determined by vectors u⃗,v⃗\vec{u}, \vec{v} and w⃗\vec{w}. Then the value of 803V\dfrac{80}{\sqrt{3}}V is
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Answer: 45

[JEE Advanced 2023 · Paper 1]

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