JEE Advanced 2024 · Paper 1

JEE Advanced 2024 Mathematics question on Limits Continuity and Differentiability

Let f(x)f(x) be a continuously differentiable function on the interval (0,∞)(0,\infty) such that f(1)=2f(1)=2 and lim⁡t→xt10f(x)−x10f(t)t9−x9=1\displaystyle\lim_{t\to x}\frac{t^{10}f(x)-x^{10}f(t)}{t^{9}-x^{9}}=1 for each x>0x>0. Then, for all x>0x>0, f(x)f(x) is equal to
  1. A.
    3111x−911x10\dfrac{31}{11x}-\dfrac{9}{11}x^{10}
  2. B.
    911x+1311x10\dfrac{9}{11x}+\dfrac{13}{11}x^{10}
  3. C.
    −911x+3111x10\dfrac{-9}{11x}+\dfrac{31}{11}x^{10}
  4. D.
    1311x+911x10\dfrac{13}{11x}+\dfrac{9}{11}x^{10}
Show answer

Correct option: B

[JEE Advanced 2024 · Paper 1]

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