JEE Advanced 2024 · Paper 2 · numerical answer

JEE Advanced 2024 Mathematics question on Sets Relations and Functions

Let f:R→Rf : \mathbb{R} \to \mathbb{R} be a function such that f(x+y)=f(x)+f(y)f(x+y) = f(x) + f(y) for all x,y∈Rx, y \in \mathbb{R}, and g:R→(0,∞)g : \mathbb{R} \to (0,\infty) be a function such that g(x+y)=g(x)g(y)g(x+y) = g(x)g(y) for all x,y∈Rx, y \in \mathbb{R}. If f ⁣(−35)=12f\!\left(\dfrac{-3}{5}\right) = 12 and g ⁣(−13)=2g\!\left(\dfrac{-1}{3}\right) = 2, then the value of (f ⁣(14)+g(−2)−8)g(0)\left(f\!\left(\dfrac{1}{4}\right) + g(-2) - 8\right)g(0) is ________.
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Answer: 51

[JEE Advanced 2024 · Paper 2]

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