JEE Advanced 2024 · Paper 2

JEE Advanced 2024 Mathematics question on Limits Continuity and Differentiability

Let f:R→Rf : \mathbb{R} \rightarrow \mathbb{R} be a function defined by
f(x)={x2sin⁡(πx2),if x≠0,0,if x=0.f(x) = \begin{cases} x^2 \sin\left(\dfrac{\pi}{x^2}\right), & \text{if } x \neq 0, \\ 0, & \text{if } x = 0. \end{cases}
Then which of the following statements is TRUE?
  1. A.
    f(x)=0f(x) = 0 has infinitely many solutions in the interval [11010,∞)\left[\dfrac{1}{10^{10}}, \infty\right).
  2. B.
    f(x)=0f(x) = 0 has no solutions in the interval [1π,∞)\left[\dfrac{1}{\pi}, \infty\right).
  3. C.
    The set of solutions of f(x)=0f(x) = 0 in the interval (0,11010)\left(0, \dfrac{1}{10^{10}}\right) is finite.
  4. D.
    f(x)=0f(x) = 0 has more than 25 solutions in the interval (1π2,1π)\left(\dfrac{1}{\pi^2}, \dfrac{1}{\pi}\right).
Show answer

Correct option: D

[JEE Advanced 2024 · Paper 2]

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