JEE Advanced 2023 · Paper 1

JEE Advanced 2023 Mathematics question on Limits Continuity and Differentiability

Let f:(0,1)→Rf:(0,1) \to \mathbb{R} be the function defined as f(x)=nf(x) = \sqrt{n} if x∈[1n+1,1n)x \in \left[\dfrac{1}{n+1}, \dfrac{1}{n}\right) where n∈Nn \in \mathbb{N}. Let g:(0,1)→Rg:(0,1) \to \mathbb{R} be a function such that ∫x2x1−tt dt<g(x)<2x\displaystyle\int_{x^2}^{x} \sqrt{\dfrac{1-t}{t}}\,dt < g(x) < 2\sqrt{x} for all x∈(0,1)x \in (0,1). Then lim⁡x→0f(x)g(x)\displaystyle\lim_{x \to 0} f(x)g(x)
  1. A.
    does NOT exist
  2. B.
    is equal to 1
  3. C.
    is equal to 2
  4. D.
    is equal to 3
Show answer

Correct option: C

[JEE Advanced 2023 · Paper 1]

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