JEE Advanced 2023 · Paper 1 · numerical answer

JEE Advanced 2023 Mathematics question on Binomial Theorem

Let aa and bb be two nonzero real numbers. If the coefficient of x5x^5 in the expansion of (ax2+7027bx)4\left(ax^2 + \dfrac{70}{27bx}\right)^4 is equal to the coefficient of x−5x^{-5} in the expansion of (ax−1bx2)7\left(ax - \dfrac{1}{bx^2}\right)^7, then the value of 2b2b is
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Answer: 3

[JEE Advanced 2023 · Paper 1]

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