JEE Advanced 2023 · Paper 1 · numerical answer

JEE Advanced 2023 Mathematics question on Sequences and Series

Let 75⋯5⏞r77\overbrace{5\cdots5}^{r}7 denote the (r+2)(r+2) digit number where the first and the last digits are 7 and the remaining rr digits are 5. Consider the sum S=77+757+7557+⋯+75⋯5⏞987S = 77 + 757 + 7557 + \cdots + 7\overbrace{5\cdots5}^{98}7. If S=75⋯5⏞997+mnS = \dfrac{7\overbrace{5\cdots5}^{99}7 + m}{n}, where mm and nn are natural numbers less than 3000, then the value of m+nm + n is
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Answer: 1219

[JEE Advanced 2023 · Paper 1]

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