JEE Advanced 2023 · Paper 1 · numerical answer

JEE Advanced 2023 Chemistry question on Equilibrium

In a one-litre flask, 6 moles of A undergoes the reaction A (g) ⇌\rightleftharpoons P (g). The progress of product formation at two temperatures (in Kelvin), T1T_1 and T2T_2, is shown in the figure:

If T1=2T2T_1 = 2T_2 and (ΔG2θ−ΔG1θ)=RT2ln⁡x\left(\Delta G_2^\theta - \Delta G_1^\theta\right) = RT_2 \ln x, then the value of x is ___.

[ΔG1θ\Delta G_1^\theta and ΔG2θ\Delta G_2^\theta are standard Gibb's free energy change for the reaction at temperatures T1T_1 and T2T_2, respectively.]
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Answer: 8

[JEE Advanced 2023 · Paper 1]

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