JEE Advanced 2023 · Paper 2 · numerical answer

JEE Advanced 2023 Mathematics question on Differential Equations

For x∈Rx \in \mathbb{R}, let y(x)y(x) be a solution of the differential equation (x2−5)dydx−2xy=−2x(x2−5)2(x^2 - 5)\dfrac{dy}{dx} - 2xy = -2x(x^2-5)^2 such that y(2)=7y(2) = 7. Then the maximum value of the function y(x)y(x) is
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Answer: 16

[JEE Advanced 2023 · Paper 2]

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